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Q:
Finding an equation of a parabola
$$a^2 + b^2 = 16 \\ y = 2ax -x^2$$
I got this equation from a multivariable problems set where it asks for the equation of the parabola, I’ve tried doing a substitution and taking the derivative but I’m still confused, any hints?
A:
$$\frac{y-4a}{a^2+4b^2}=\frac{2x-2a^2-4b^2}{4a^2+4b^2}=x-\frac{a^2+b^2}{2a}$$
Another substitution would be $x=a+2b$. This gives you
$$\frac{y-4a}{a^2+b^2}=\frac{a+2b-4a}{a^2+b^2}=\frac{b-a}{a+2b}=\frac{b-a}{b-a+2a}$$
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