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Watch Raja Ki Aayegi Baarat Full movie in hindi free download 3gp Sometime movie in hindi free download 3gp Watch Raja Ki Aayegi Baarat Full movie in hindi free download 3gpQ: Finding the maximum probability of an outcome You get an coin with the probability of heads equal to 0.4988. You toss the coin $2n$ times. What is the maximum probability you will see $n$ heads in a row? The answer is $$1 -\left(\frac{\binom{2n}{n}}{\binom{2n}{0}}\right)^{\frac{1}{2n}}$$ I don’t quite understand how the first term is considered. Any help would be great. Thanks. A: The first term is the probability of the $n$-th trial being a success. Then the answer is the probability that you see an $n$-sequence of successes, given that the first head is the $n$-th success. For $n>1$, this probability is $$P(n, 1) = 1 – \left(\frac{\binom{2n}{n}}{\binom{2n}{0}}\right)^{\frac{1}{2n}}.$$ Q: Ora-12541, ORA-12541: TNS:no listener I am trying to connect to oracle using a.NET app running on Windows. The machine contains the Oracle client 12.2.0.1 installed and we have multiple instances of oracle running on the machine. Here is the code that i have used to connect: String driverName = Oracle.DataAccess.Client.OracleClient.OracleClientFactory.ClientName; OracleConnection conn = new OracleConnection(@»Data Source=(DESCRIPTION=(ADDRESS_LIST=(ADDRESS=(PROTOCOL=TCP)(HOST=127.0.0.1)(PORT=1521)))(CONNECT_DATA=(SERVER=DEDICATED)(SERVICE_NAME=xe)(FAX=ON)))(ORACLE_SID=s1))»); using (conn) { conn.Open(); Console.WriteLine(«Connected!»); }